3.599 \(\int \frac {(a+b x^3)^{2/3}}{x^{12} (a d-b d x^3)} \, dx\)

Optimal. Leaf size=236 \[ \frac {b^{11/3} \log \left (a d-b d x^3\right )}{3 \sqrt [3]{2} a^4 d}-\frac {b^{11/3} \log \left (\sqrt [3]{2} \sqrt [3]{b} x-\sqrt [3]{a+b x^3}\right )}{\sqrt [3]{2} a^4 d}+\frac {2^{2/3} b^{11/3} \tan ^{-1}\left (\frac {\frac {2 \sqrt [3]{2} \sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}+1}{\sqrt {3}}\right )}{\sqrt {3} a^4 d}-\frac {293 b^3 \left (a+b x^3\right )^{2/3}}{440 a^4 d x^2}-\frac {49 b^2 \left (a+b x^3\right )^{2/3}}{220 a^3 d x^5}-\frac {13 b \left (a+b x^3\right )^{2/3}}{88 a^2 d x^8}-\frac {\left (a+b x^3\right )^{2/3}}{11 a d x^{11}} \]

[Out]

-1/11*(b*x^3+a)^(2/3)/a/d/x^11-13/88*b*(b*x^3+a)^(2/3)/a^2/d/x^8-49/220*b^2*(b*x^3+a)^(2/3)/a^3/d/x^5-293/440*
b^3*(b*x^3+a)^(2/3)/a^4/d/x^2+1/6*b^(11/3)*ln(-b*d*x^3+a*d)*2^(2/3)/a^4/d-1/2*b^(11/3)*ln(2^(1/3)*b^(1/3)*x-(b
*x^3+a)^(1/3))*2^(2/3)/a^4/d+1/3*2^(2/3)*b^(11/3)*arctan(1/3*(1+2*2^(1/3)*b^(1/3)*x/(b*x^3+a)^(1/3))*3^(1/2))/
a^4/d*3^(1/2)

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Rubi [C]  time = 17.60, antiderivative size = 391, normalized size of antiderivative = 1.66, number of steps used = 2, number of rules used = 2, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {511, 510} \[ -\frac {-54 b x^3 \left (a-b x^3\right )^2 \left (5 a+6 b x^3\right ) \, _3F_2\left (\frac {1}{3},2,2;1,\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+54 b x^3 \left (a-b x^3\right )^3 \, _4F_3\left (\frac {1}{3},2,2,2;1,1,\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )-180 a^2 b^2 x^6 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+198 a^2 b^2 x^6 \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+99 a^2 b^2 x^6-160 a^3 b x^3 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+396 a^3 b x^3 \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+85 a^3 b x^3+40 a^4-324 b^4 x^{12} \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )-594 b^4 x^{12} \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )-216 a b^3 x^9 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{b x^3+a}\right )+135 a b^3 x^9+81 b^4 x^{12}}{440 a^4 d x^{11} \sqrt [3]{a+b x^3}} \]

Warning: Unable to verify antiderivative.

[In]

Int[(a + b*x^3)^(2/3)/(x^12*(a*d - b*d*x^3)),x]

[Out]

-(40*a^4 + 85*a^3*b*x^3 + 99*a^2*b^2*x^6 + 135*a*b^3*x^9 + 81*b^4*x^12 - 160*a^3*b*x^3*Hypergeometric2F1[1/3,
1, 4/3, (2*b*x^3)/(a + b*x^3)] - 180*a^2*b^2*x^6*Hypergeometric2F1[1/3, 1, 4/3, (2*b*x^3)/(a + b*x^3)] - 216*a
*b^3*x^9*Hypergeometric2F1[1/3, 1, 4/3, (2*b*x^3)/(a + b*x^3)] - 324*b^4*x^12*Hypergeometric2F1[1/3, 1, 4/3, (
2*b*x^3)/(a + b*x^3)] + 396*a^3*b*x^3*Hypergeometric2F1[1/3, 2, 4/3, (2*b*x^3)/(a + b*x^3)] + 198*a^2*b^2*x^6*
Hypergeometric2F1[1/3, 2, 4/3, (2*b*x^3)/(a + b*x^3)] - 594*b^4*x^12*Hypergeometric2F1[1/3, 2, 4/3, (2*b*x^3)/
(a + b*x^3)] - 54*b*x^3*(a - b*x^3)^2*(5*a + 6*b*x^3)*HypergeometricPFQ[{1/3, 2, 2}, {1, 4/3}, (2*b*x^3)/(a +
b*x^3)] + 54*b*x^3*(a - b*x^3)^3*HypergeometricPFQ[{1/3, 2, 2, 2}, {1, 1, 4/3}, (2*b*x^3)/(a + b*x^3)])/(440*a
^4*d*x^11*(a + b*x^3)^(1/3))

Rule 510

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a^p*c^q
*(e*x)^(m + 1)*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, -((b*x^n)/a), -((d*x^n)/c)])/(e*(m + 1)), x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 511

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[(a^IntPa
rt[p]*(a + b*x^n)^FracPart[p])/(1 + (b*x^n)/a)^FracPart[p], Int[(e*x)^m*(1 + (b*x^n)/a)^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {\left (a+b x^3\right )^{2/3}}{x^{12} \left (a d-b d x^3\right )} \, dx &=\frac {\left (a+b x^3\right )^{2/3} \int \frac {\left (1+\frac {b x^3}{a}\right )^{2/3}}{x^{12} \left (a d-b d x^3\right )} \, dx}{\left (1+\frac {b x^3}{a}\right )^{2/3}}\\ &=-\frac {40 a^4+85 a^3 b x^3+99 a^2 b^2 x^6+135 a b^3 x^9+81 b^4 x^{12}-160 a^3 b x^3 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )-180 a^2 b^2 x^6 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )-216 a b^3 x^9 \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )-324 b^4 x^{12} \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )+396 a^3 b x^3 \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )+198 a^2 b^2 x^6 \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )-594 b^4 x^{12} \, _2F_1\left (\frac {1}{3},2;\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )-54 b x^3 \left (a-b x^3\right )^2 \left (5 a+6 b x^3\right ) \, _3F_2\left (\frac {1}{3},2,2;1,\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )+54 b x^3 \left (a-b x^3\right )^3 \, _4F_3\left (\frac {1}{3},2,2,2;1,1,\frac {4}{3};\frac {2 b x^3}{a+b x^3}\right )}{440 a^4 d x^{11} \sqrt [3]{a+b x^3}}\\ \end {align*}

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Mathematica [A]  time = 5.35, size = 196, normalized size = 0.83 \[ \frac {\frac {2^{2/3} b^{11/3} \left (\log \left (\frac {2^{2/3} b^{2/3} x^2}{\left (a x^3+b\right )^{2/3}}+\frac {\sqrt [3]{2} \sqrt [3]{b} x}{\sqrt [3]{a x^3+b}}+1\right )-2 \log \left (1-\frac {\sqrt [3]{2} \sqrt [3]{b} x}{\sqrt [3]{a x^3+b}}\right )+2 \sqrt {3} \tan ^{-1}\left (\frac {\frac {2 \sqrt [3]{2} \sqrt [3]{b} x}{\sqrt [3]{a x^3+b}}+1}{\sqrt {3}}\right )\right )}{a^4}-\frac {3 \left (a+b x^3\right )^{2/3} \left (40 a^3+65 a^2 b x^3+98 a b^2 x^6+293 b^3 x^9\right )}{220 a^4 x^{11}}}{6 d} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(a + b*x^3)^(2/3)/(x^12*(a*d - b*d*x^3)),x]

[Out]

((-3*(a + b*x^3)^(2/3)*(40*a^3 + 65*a^2*b*x^3 + 98*a*b^2*x^6 + 293*b^3*x^9))/(220*a^4*x^11) + (2^(2/3)*b^(11/3
)*(2*Sqrt[3]*ArcTan[(1 + (2*2^(1/3)*b^(1/3)*x)/(b + a*x^3)^(1/3))/Sqrt[3]] - 2*Log[1 - (2^(1/3)*b^(1/3)*x)/(b
+ a*x^3)^(1/3)] + Log[1 + (2^(2/3)*b^(2/3)*x^2)/(b + a*x^3)^(2/3) + (2^(1/3)*b^(1/3)*x)/(b + a*x^3)^(1/3)]))/a
^4)/(6*d)

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fricas [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^12/(-b*d*x^3+a*d),x, algorithm="fricas")

[Out]

Timed out

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {{\left (b x^{3} + a\right )}^{\frac {2}{3}}}{{\left (b d x^{3} - a d\right )} x^{12}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^12/(-b*d*x^3+a*d),x, algorithm="giac")

[Out]

integrate(-(b*x^3 + a)^(2/3)/((b*d*x^3 - a*d)*x^12), x)

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maple [F]  time = 0.58, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \,x^{3}+a \right )^{\frac {2}{3}}}{\left (-b d \,x^{3}+a d \right ) x^{12}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^(2/3)/x^12/(-b*d*x^3+a*d),x)

[Out]

int((b*x^3+a)^(2/3)/x^12/(-b*d*x^3+a*d),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\int \frac {{\left (b x^{3} + a\right )}^{\frac {2}{3}}}{{\left (b d x^{3} - a d\right )} x^{12}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(2/3)/x^12/(-b*d*x^3+a*d),x, algorithm="maxima")

[Out]

-integrate((b*x^3 + a)^(2/3)/((b*d*x^3 - a*d)*x^12), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (b\,x^3+a\right )}^{2/3}}{x^{12}\,\left (a\,d-b\,d\,x^3\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^3)^(2/3)/(x^12*(a*d - b*d*x^3)),x)

[Out]

int((a + b*x^3)^(2/3)/(x^12*(a*d - b*d*x^3)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**(2/3)/x**12/(-b*d*x**3+a*d),x)

[Out]

Timed out

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